Palindromic Number in C++

Welcome to the Palindromic Number in C++ page! Here, you’ll find the source code for this program as well as a description of how the program works.

Current Solution

#include <iostream>
#include <string.h>
#include <stdlib.h>
#include <ctype.h>

using namespace std;

void palindromic_number(int number)
{
    int temp = number, reversed_number = 0;

    while (temp > 0)
    {
        reversed_number = (reversed_number * 10) + (temp % 10);
        temp = (int)(temp / 10);
    }
    if (number < 0)
    {
        cout << "Usage: please input a non-negative integer";
        exit(1);
    }
    else
    {
        if (reversed_number == number)
        {
            cout << "true";
        }
        else
        {
            cout << "false";
        }
    }
}

int is_int(char **argv)
{
    int j = 0;
    while (isdigit(argv[1][j]))
        ++j;

    if (strlen(argv[1]) != j)
    {
        return 1;
    }
    else
    {
        return 0;
    }
}

int main(int argc, char **argv)
{
    if (argc != 2 || is_int(argv))
    {
        cout << "Usage: please input a non-negative integer";
        return (1);
    }
    palindromic_number(atoi(argv[1]));
    return (0);
}

Palindromic Number in C++ was written by:

• Jeremy Grifski
• smjalageri

If you see anything you’d like to change or update, please consider contributing.

Note: The solution shown above is the current solution in the Sample Programs repository as of Oct 11 2022 01:31:51. The solution was first committed on Nov 01 2021 10:06:42. As a result, documentation below may be outdated.

How to Implement the Solution

No ‘How to Implement the Solution’ section available. Please consider contributing.

How to Run the Solution

No ‘How to Run the Solution’ section available. Please consider contributing.