A Collection of Code Snippets in as Many Programming Languages as Possible

This project is maintained by TheRenegadeCoder

Welcome to the Quick Sort in Dart page! Here, you'll find the source code for this program as well as a description of how the program works.

```
import 'dart:io';
/**
*
* Merge sort Algorithm from introduction to algorithm
*/
quicksort(List lst,int start,int end){
if(start < end){
int mid = partition(lst,start,end);
//How to use recursive calls
//Divide and conquer
quicksort(lst, start, mid-1);
quicksort(lst, mid, end);
}
}
partition(List lst,int start,int end){
//Sort the array accordingly to the pivot_element
var pivot_element = lst[end];
var start_position = start -1;
for (var i = start; i < end; i++){
if(lst[i] <= pivot_element){
start_position++;
swap(lst, start_position, i);
}
}
swap(lst, start_position+1, end);
return start_position+1;
}
swap(List<int> lst, int position, int position2){
var tmp = lst[position];
lst[position] = lst[position2];
lst[position2] = tmp;
}
List<int>parseInput(List<String> input){
List<int> lst = [];
var inputString = input.join().replaceAll(" ", "").replaceAll("'", "").split(",");
for(var stringNumber in inputString){
lst.add(int.parse(stringNumber));
}
return lst;
}
exitWithError() {
print(
'Usage: please provide a list of at least two integers to sort in the format "1, 2, 3, 4, 5"');
exit(1);
}
main(List<String> args) {
try {
List<int> lst = parseInput(args);
if (lst.length <= 1) exitWithError();
quicksort(lst, 0, lst.length - 1);
print(lst.join(", "));
}catch (e) {
exitWithError();
}
}
```

Quick Sort in Dart was written by:

- Oxymora

If you see anything you'd like to change or update, please consider contributing.

**Note**: The solution shown above is the current solution in the Sample Programs repository as of Nov 04 2019 12:06:42. The solution was first committed on Oct 28 2019 14:45:55. As a result, documentation below may be outdated.

No 'How to Implement the Solution' section available. Please consider contributing.

No 'How to Run the Solution' section available. Please consider contributing.