A Collection of Code Snippets in as Many Programming Languages as Possible
This project is maintained by TheRenegadeCoder
Welcome to the Minimum Spanning Tree in C# page! Here, you'll find the source code for this program as well as a description of how the program works.
if (args is not [var input] || !TryParseMatrix(input.AsSpan(), out var matrix, out int n))
return ExitWithUsage();
int weight = MinimumSpanningTreeWeight(matrix, n);
if (weight < 0)
return ExitWithUsage();
Console.WriteLine(weight);
return 0;
static int MinimumSpanningTreeWeight(List<int> matrix, int n)
{
var inMst = new bool[n];
var minEdge = new int[n];
Array.Fill(minEdge, int.MaxValue);
minEdge[0] = 0;
int total = 0;
for (int added = 0; added < n; added++)
{
int bestWeight = int.MaxValue;
int u = -1;
for (int i = 0; i < n; i++)
{
if (!inMst[i] && minEdge[i] < bestWeight)
{
bestWeight = minEdge[i];
u = i;
}
}
if (u < 0)
return -1;
inMst[u] = true;
total += bestWeight;
int row = u * n;
for (int v = 0; v < n; v++)
{
int w = matrix[row + v];
if (w != 0 && !inMst[v] && w < minEdge[v])
minEdge[v] = w;
}
}
return total;
}
static bool TryParseMatrix(ReadOnlySpan<char> view, out List<int> numbers, out int dimension)
{
numbers = null!;
dimension = 0;
if (view.IsWhiteSpace())
return false;
int expected = view.Count(',') + 1;
if (expected < 4) return false;
var list = new List<int>(expected);
while (!view.IsEmpty)
{
int i = view.IndexOf(',');
var token = i >= 0 ? view[..i] : view;
view = i >= 0 ? view[(i + 1)..] : [];
if (!int.TryParse(token, out int v))
return false;
list.Add(v);
}
int d = (int)Math.Sqrt(list.Count);
if (d * d != list.Count)
return false;
numbers = list;
dimension = d;
return true;
}
static int ExitWithUsage()
{
Console.Error.WriteLine("""Usage: please provide a comma-separated list of integers""");
return 1;
}
Minimum Spanning Tree in C# was written by:
If you see anything you'd like to change or update, please consider contributing.
No 'How to Implement the Solution' section available. Please consider contributing.
No 'How to Run the Solution' section available. Please consider contributing.