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Welcome to the Longest Common Subsequence in Python page! Here, you'll find the source code for this program as well as a description of how the program works.
import sys def input_list(list_str): return [int(x.strip(" "), 10) for x in list_str.split(',')] def longest(s1, s2): return s1 if len(s1) > len(s2) else s2 def lcs(s1, s2): if len(s1) == 0 or len(s2) == 0: return  elif s1[-1] == s2[-1]: return lcs(s1[:-1], s2[:-1]) + [s1[-1]] elif s1[-1] != s2[-1]: return longest(lcs(s1, s2[:-1]), lcs(s1[:-1], s2)) def exit_with_error(): print('Usage: please provide two lists in the format "1, 2, 3, 4, 5"') sys.exit(1) def main(args): try: lst1 = input_list(args) lst2 = input_list(args) print(lcs(lst1, lst2)) except (IndexError, ValueError): exit_with_error() if __name__ == "__main__": main(sys.argv[1:])
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Note: The solution shown above is the current solution in the Sample Programs repository as of Mar 21 2019 16:33:32. The solution was first committed on Oct 16 2018 08:04:37. As a result, documentation below may be outdated.
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