Linear Search in C++

Welcome to the Linear Search in C++ page! Here, you’ll find the source code for this program as well as a description of how the program works.

Current Solution

#include <iostream>
#include <vector>
#include <string>
#include <cstring>
using namespace std;

int main(int argc, char *argv[])
{
    string error = "Usage: please provide a list of integers (\"1, 4, 5, 11, 12\") and the integer to find (\"11\")";

    if (argc != 3)
    {
        cout << error << endl;
        return 1;
    }
    int numberLength = strlen(argv[1]);
    int keyLength = strlen(argv[1]);

    if (numberLength == 0 || keyLength == 0)
    {
        cout << error << endl;
        return 1;
    }
    vector<int> arr;
    string temp = "";
    for (int i = 0; i < numberLength; i++)
    {
        if (argv[1][i] == ',')
        {
            arr.push_back(stoi(temp));
            temp = "";
        }
        else
        {
            temp = temp + argv[1][i];
        }
    }
    arr.push_back(stoi(temp));
    int key = stoi(argv[2]);
    bool found = false;
    for (int i = 0; i < arr.size(); i++)
    {
        if (arr[i] == key)
        {
            found = true;
        }
    }
    if (found)
    {
        cout << "true";
    }
    else
    {
        cout << "false";
    }
}

Linear Search in C++ was written by:

• Jeremy Grifski
• rzuckerm
• Vipin Yadav

If you see anything you’d like to change or update, please consider contributing.

Note: The solution shown above is the current solution in the Sample Programs repository as of Jan 29 2023 21:43:56. The solution was first committed on Oct 03 2022 18:59:58. As a result, documentation below may be outdated.

How to Implement the Solution

No ‘How to Implement the Solution’ section available. Please consider contributing.

How to Run the Solution

No ‘How to Run the Solution’ section available. Please consider contributing.