Fizz Buzz in Typescript

Published on 11 October 2018 (Updated: 11 October 2018)

Welcome to the Fizz Buzz in Typescript page! Here, you'll find the source code for this program as well as a description of how the program works.

Current Solution

let line: string;

for (let i = 1; i <= 100; i++) {
   if (i % 3 == 0 && i % 5 == 0) {
      line = "FizzBuzz";
   } else if (i % 3 == 0) {
      line = "Fizz";
   } else if (i % 5 == 0) {
      line = "Buzz";
   } else {
      line = String(i);
   }
   console.log(line);
}

Fizz Buzz in Typescript was written by:

If you see anything you'd like to change or update, please consider contributing.

Note: The solution shown above is the current solution in the Sample Programs repository as of May 15 2023 16:26:37. The solution was first committed on Oct 11 2018 20:07:08. As a result, documentation below may be outdated.

How to Implement the Solution

No 'How to Implement the Solution' section available. Please consider contributing.

How to Run the Solution

No 'How to Run the Solution' section available. Please consider contributing.