Fizz Buzz in C*

Published on 28 October 2025 (Updated: 28 October 2025)

Welcome to the Fizz Buzz in C* page! Here, you'll find the source code for this program as well as a description of how the program works.

Current Solution

void main()
{
    for (int i = 1; i <= 100; i++) {
    if (i % 15 == 0)
        println("FizzBuzz");
    else if (i % 3 == 0)
        println("Fizz");
    else if (i % 5 == 0)
        println("Buzz");
    else
        println(i);
    }
}

Fizz Buzz in C* was written by:

If you see anything you'd like to change or update, please consider contributing.

How to Implement the Solution

No 'How to Implement the Solution' section available. Please consider contributing.

How to Run the Solution

No 'How to Run the Solution' section available. Please consider contributing.