A Collection of Code Snippets in as Many Programming Languages as Possible
This project is maintained by TheRenegadeCoder
Welcome to the Binary Search in C++ page! Here, you'll find the source code for this program as well as a description of how the program works.
#include <iostream>
#include <bits/stdc++.h>
using namespace std;
void handle_error()
{
cout << "Usage: please provide a list of sorted integers (\"1, 4, 5, 11, 12\") and the integer to find (\"11\")" << endl;
exit(0);
}
int check(string s)
{
int x1 = 0, x2 = s.size() - 1;
for (int i = 0; i < s.size(); i++)
{
if (s[i] != ' ')
{
x1 = i;
break;
}
}
for (int i = s.size() - 1; i >= x1; i--)
{
if (s[i] != ' ')
{
x2 = i;
break;
}
}
for (int i = x1; i <= x2; i++)
{
if (s[i] == ' ')
{
handle_error();
}
}
return stoi(s);
}
vector<int> convert(string s)
{
if (s.size() == 0)
{
handle_error();
}
vector<int> v;
string num = "";
for (int i = 0; i < s.size(); i++)
{
if ((int)s[i] >= 48 && (int)s[i] <= 57 || s[i] == ' ')
{
num += s[i];
}
else if (s[i] == ',')
{
v.push_back(check(num));
num = "";
}
else
{
handle_error();
}
}
if (num.size() > 0)
{
v.push_back(check(num));
}
return v;
}
int main(int argc, char *argv[])
{
if (argc < 3)
{
handle_error();
}
vector<int> v = convert(argv[1]);
int num = check(argv[2]);
for (int i = 0; i < v.size() - 1; i++)
{
if (v[i] > v[i + 1])
{
handle_error();
}
}
int start = 0, end = v.size();
string ans = "false";
while (start < end)
{
int mid = (start + end) / 2;
if (num < v[mid])
{
end = mid;
}
else if (v[mid] < num)
{
start = mid + 1;
}
else if (v[mid] == num)
{
ans = "true";
break;
}
}
if (start > end)
{
ans = "false";
}
cout << ans << endl;
}
Binary Search in C++ was written by:
If you see anything you'd like to change or update, please consider contributing.
Note: The solution shown above is the current solution in the Sample Programs repository as of Oct 10 2022 16:05:09. The solution was first committed on Oct 27 2019 18:00:32. As a result, documentation below may be outdated.
No 'How to Implement the Solution' section available. Please consider contributing.
No 'How to Run the Solution' section available. Please consider contributing.