Baklava in Elixir

Published on 22 May 2019 (Updated: 22 May 2019)

Welcome to the Baklava in Elixir page! Here, you'll find the source code for this program as well as a description of how the program works.

Current Solution

``````defmodule Baklava do
@doc """
Create baklava where the top has 10 spaces and then 1 asterisk.
"""
@spec baklava() :: String.t()
def baklava, do: baklava_grow(10, 1)

@doc """
Recursively grow the baklava until spaces <= zero.
"""
@spec baklava_grow(spaces :: integer, asterisks :: integer) :: String.t()
def baklava_grow(spaces, asterisks) when spaces <= 0 do
line(0, asterisks) <> "\n" <> baklava_shrink(1, asterisks - 2)
end

def baklava_grow(spaces, asterisks) do
line(spaces, asterisks) <> "\n" <> baklava_grow(spaces - 1, asterisks + 2)
end

@doc """
Recursively shrink the baklava until asterisks <= zero.
"""
@spec baklava_shrink(spaces :: integer, asterisks :: integer) :: String.t()
def baklava_shrink(spaces, asterisks) when asterisks <= 1, do: line(spaces, 1)

def baklava_shrink(spaces, asterisks) do
line(spaces, asterisks) <> "\n" <> baklava_shrink(spaces + 1, asterisks - 2)
end

@doc """
Return a single line of the baklava.
"""
@spec line(spaces :: integer, asterisks :: integer) :: String.t()
def line(spaces, asterisks) do
String.duplicate(" ", spaces) <> String.duplicate("*", asterisks)
end
end

Baklava.baklava() |> IO.puts()

``````

Baklava in Elixir was written by:

• Oleksii Filonenko

If you see anything you'd like to change or update, please consider contributing.

How to Implement the Solution

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How to Run the Solution

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