Baklava in C++

Welcome to the Baklava in C++ page! Here, you'll find the source code for this program as well as a description of how the program works.

Current Solution

#include <iostream>

using namespace std;

int main(int argc, char *argv[])
{
    int i, j, k, n;
    n = 21;
    for (i = 1; i <= (n + 1) / 2;)
    {
        for (k = 1; (n + 1) / 2 - i >= k; k++)
            cout << " ";
        for (j = 1; j < 2 * i; j++)
            cout << "*";
        cout << "\n";
        i++;
    }
    if (2 * i - 1 >= n)
    {
        for (i = (n + 1) / 2 - 1; i >= 1; i--)
        {
            for (k = 1; (n + 1) / 2 - i >= k; k++)
                cout << " ";
            for (j = 1; j < 2 * i; j++)
                cout << "*";
            cout << "\n";
        }
    }
    return (0);
}

Baklava in C++ was written by:

• Behnam Ahmad khan beigi
• Jeremy Grifski
• yottanami

If you see anything you'd like to change or update, please consider contributing.

Note: The solution shown above is the current solution in the Sample Programs repository as of Oct 10 2022 16:05:09. The solution was first committed on Oct 09 2019 12:57:32. As a result, documentation below may be outdated.

How to Implement the Solution

No 'How to Implement the Solution' section available. Please consider contributing.

How to Run the Solution

No 'How to Run the Solution' section available. Please consider contributing.