Baklava in C++

Welcome to the Baklava in C++ page! Here, you'll find the source code for this program as well as a description of how the program works.

Current Solution

#include <iostream>

using namespace std;

int main(int argc, char *argv[])
{
    int i, j, k, n;
    n = 21;
    for (i = 1; i <= (n + 1) / 2;)
    {
        for (k = 1; (n + 1) / 2 - i >= k; k++)
            cout << " ";
        for (j = 1; j < 2 * i; j++)
            cout << "*";
        cout << "\n";
        i++;
    }
    if (2 * i - 1 >= n)
    {
        for (i = (n + 1) / 2 - 1; i >= 1; i--)
        {
            for (k = 1; (n + 1) / 2 - i >= k; k++)
                cout << " ";
            for (j = 1; j < 2 * i; j++)
                cout << "*";
            cout << "\n";
        }
    }
    return (0);
}

Baklava in C++ was written by:

• Behnam Ahmad khan beigi
• Jeremy Grifski
• yottanami

If you see anything you'd like to change or update, please consider contributing.

How to Implement the Solution

No 'How to Implement the Solution' section available. Please consider contributing.

How to Run the Solution

No 'How to Run the Solution' section available. Please consider contributing.