Maximum Subarray in Commodore Basic

Published on 14 October 2023 (Updated: 14 October 2023)

Welcome to the Maximum Subarray in Commodore Basic page! Here, you'll find the source code for this program as well as a description of how the program works.

Current Solution

10 DIM A(99)
20 GOSUB 2000: REM Get array
25 REM Error if invalid or not end of input/value
30 IF V = 0 OR C >= 0 THEN GOTO 200
40 GOSUB 3000: REM Perform maximum subarray
50 S$ = STR$(BS)
60 IF BS >= 0 THEN S$ = MID$(S$, 2)
70 PRINT S$
80 END
200 Q$ = CHR$(34): REM quote
210 PRINT "Usage: Please provide a list of integers in the format: ";
220 PRINT Q$; "1, 2, 3, 4, 5"; Q$
230 END
1000 REM Read input value one character at a time since Commodore BASIC
1001 REM has trouble reading line from stdin properly
1002 REM NR = number
1003 REM V = 1 if valid number, 0 otherwise
1004 REM C = -2 if end of input, -1 if end of value,
1005 REM   32 if whitespace, ASCII code of last character otherwise
1006 REM Initialize
1010 NR = 0
1020 V = 0
1030 S = 1
1035 REM Loop while leading spaces
1040 GOSUB 1500
1050 IF C = 43 OR C = 45 THEN GOTO 1100: REM + or -
1060 IF C >= 48 AND C <= 57 THEN GOTO 1150: REM 0 to 9
1070 IF C = 32 THEN GOTO 1040: REM whitespace
1080 RETURN: REM other character
1085 REM Loop while sign
1090 GOSUB 1500
1100 IF C = 43 THEN GOTO 1090: REM +
1110 IF C >= 48 AND C <= 57 THEN GOTO 1150: REM 0 to 9
1120 IF C <> 45 THEN RETURN: REM not -
1130 S = -S
1140 GOTO 1090
1145 REM Set valid flag
1150 V = 1
1155 REM Loop while digits
1160 NR = (ABS(NR) * 10 + C - 48) * S
1170 GOSUB 1500
1180 IF C >= 48 AND C <= 57 THEN GOTO 1160: REM 0 to 9
1185 REM Loop while trailing spaces
1190 IF C < 0 OR C <> 32 THEN RETURN: REM end character or not whitespace
1200 GOSUB 1500
1210 GOTO 1180
1500 REM Get input character
1501 REM A$ = input character
1502 REM C = One of the following:
1502 REM - -1 if end of value
1503 REM - -2 if end of input
1504 REM - 32 if whitespace
1505 REM - ASCII code otherwise
1510 GET A$
1520 C = ASC(A$)
1530 IF C = 13 THEN C = -1
1540 IF C = 255 THEN C = -2
1550 IF C = 9 OR C = 10 THEN C = 32
1560 RETURN
2000 REM Read array value
2001 REM A contains array value
2002 REM NA contains length of array
2003 REM V = 1 if valid number, 0 otherwise
2004 REM C = -2 if end of input, -1 if end of value,
2005 REM   32 if whitespace, ASCII code of last character otherwise
2006 REM Initialize
2010 NA = 0
2020 GOSUB 1000: REM Read input value
2030 IF V = 0 THEN RETURN: REM invalid
2040 A(NA) = NR
2050 NA = NA + 1
2060 IF C < 0 THEN RETURN: REM end of input or value
2070 IF C = 44 THEN GOTO 2020: REM comma, get next value
2080 V = 0
2090 RETURN
3000 REM Find maximum subarray using Kadane's algorithm.
3001 REM Source:
3002 REM https://en.wikipedia.org/wiki/Maximum_subarray_problem
3003 REM #No_empty_subarrays_admitted
3004 REM Inputs:
3005 REM - A contains array
3006 REM - NA contains size of array
3007 REM Outputs: BS contains answer
3010 REM Initialize best sum to -infinity and current sum to 0
3020 BS = -1.70141183E38: REM (smallest negative number)
3030 CS = 0
3040 IF NA < 1 THEN BS = 0: GOTO 3130
3050 FOR I = 0 TO NA - 1
3060     REM If current sum < 0, set it to current value
3070     REM Else, add current value to current sum
3080     IF CS < 0 THEN CS = 0
3090     CS = CS + A(I)
3100     REM If current sum greater than best sum, update best sum
3110     IF CS > BS THEN BS = CS
3120 NEXT I
3130 RETURN

Maximum Subarray in Commodore Basic was written by:

If you see anything you'd like to change or update, please consider contributing.

How to Implement the Solution

No 'How to Implement the Solution' section available. Please consider contributing.

How to Run the Solution

No 'How to Run the Solution' section available. Please consider contributing.