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Welcome to the Longest Palindromic Substring in C++ page! Here, you'll find the source code for this program as well as a description of how the program works.
#include <algorithm>
#include <iostream>
#include <string>
#include <string_view>
#include <vector>
std::string_view find_longest_palindrome(std::string_view s) {
if (s.empty()) return {};
std::string t;
t.reserve(s.size() * 2 + 3);
t += '^';
for (const char c : s) {
t += '#';
t += c;
}
t += "#$";
const int n = static_cast<int>(t.size());
std::vector<int> radii(n, 0);
int center = 0;
int right_boundary = 0;
for (int i = 1; i < n - 1; ++i) {
const int mirror = 2 * center - i;
if (i < right_boundary) {
radii[i] = std::min(right_boundary - i, radii[mirror]);
}
while (t[i + (1 + radii[i])] == t[i - (1 + radii[i])]) {
++radii[i];
}
if (i + radii[i] > right_boundary) {
center = i;
right_boundary = i + radii[i];
}
}
const auto max_it = std::ranges::max_element(radii);
const int max_radius = *max_it;
const int center_idx =
static_cast<int>(std::distance(radii.begin(), max_it));
return s.substr((center_idx - max_radius - 1) / 2, max_radius);
}
[[noreturn]] void usage() {
std::cerr << "Usage: please provide a string that contains at least one "
"palindrome\n";
std::exit(1);
}
int main(int argc, char* argv[]) {
if (argc != 2) usage();
std::string_view input{argv[1]};
if (input.empty()) usage();
auto result = find_longest_palindrome(input);
if (result.length() <= 1 && input.length() > 1) {
usage();
}
std::cout << result << "\n";
return 0;
}
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