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Welcome to the Longest Common Subsequence in Java page! Here, you'll find the source code for this program as well as a description of how the program works.
import java.util.*;
public class LongestCommonSubsequence {
static ArrayList<String> split_strings(String str) {
String word = "";
char dl = ',';
str = str + dl;
ArrayList<String> substr_list = new ArrayList<>();
for (int i = 0; i < str.length(); i++) {
if (str.charAt(i) != dl)
word = word + str.charAt(i);
else {
if ((int) word.length() != 0)
substr_list.add(word);
word = "";
}
}
return substr_list;
}
static void longest_common_subsequence(ArrayList<String> arr1, ArrayList<String> arr2) {
int[][] array = new int[arr1.size() + 1][arr2.size() + 1];
for (int i = 0; i < array.length; i++) {
for (int j = 0; j < array[0].length; j++) {
if (i == 0 || j == 0) {
array[i][j] = 0;
} else if (arr1.get(i - 1).equals(arr2.get(j - 1))) {
array[i][j] = 1 + array[i - 1][j - 1];
} else {
array[i][j] = Math.max(array[i - 1][j], array[i][j - 1]);
}
}
}
ArrayList<String> lcs = new ArrayList<>();
int x = array.length - 1;
int y = array[0].length - 1;
while (x > 0 && y > 0) {
if (arr1.get(x - 1).equals(arr2.get(y - 1))) {
lcs.add(0, arr1.get(x - 1));
x--;
y--;
} else {
if (array[x - 1][y] > array[x][y - 1])
x--;
else
y--;
}
}
for (int element = 0; element < lcs.size() - 1; element++) {
System.out.print(lcs.get(element) + ",");
}
System.out.println(lcs.get(lcs.size() - 1));
}
public static void main(String args[]) {
if (args.length < 2 || args[0] == "" || args[1] == "") {
System.out.println("Usage: please provide two lists in the format \"1, 2, 3, 4, 5\"");
return;
}
ArrayList<String> arr1 = split_strings(args[0]);
ArrayList<String> arr2 = split_strings(args[1]);
longest_common_subsequence(arr1, arr2);
}
}
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