A Collection of Code Snippets in as Many Programming Languages as Possible
This project is maintained by TheRenegadeCoder
Welcome to the Longest Common Subsequence in C page! Here, you'll find the source code for this program as well as a description of how the program works.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
long long arr[100000],arr1[100000];
int lc[1000][1000];
long long ans[100000];
int indic;
long long get_val(int tmp[],int len){
long long value=0,mult=1;
for(int i=len-1;i>-1;--i){
if(tmp[i]==' '-'0'){
printf("Usage: please provide two lists in the format \"1, 2, 3, 4, 5\"");
exit(0);
}
value+=tmp[i]*mult;
mult*=10;
}
return value;
}
int max(int a,int b){
return a>b?a:b;
}
int lcs(int l,int r){
if(l<0||r<0)return 0;
if(lc[l][r]!=-1)return lc[l][r];
if(arr[l]==arr1[r])lc[l][r]=lcs(l-1,r-1)+1;
lc[l][r]=max(lc[l][r],max(lcs(l,r-1),lcs(l-1,r)));
return lc[l][r];
}
void find(int l,int r){
if(l<0||r<0)return ;
if(arr[l]==arr1[r]){
ans[indic++]=arr[l];
find(l-1,r-1);
}
else if(lc[l-1][r]==lc[l][r])find(l-1,r);
else find(l,r-1);
}
int main(int argc,char **argv)
{
if(argv[1]==NULL||strlen(argv[1])==0||argv[2]==NULL||strlen(argv[2])==0){
printf("Usage: please provide two lists in the format \"1, 2, 3, 4, 5\"");
return 0;
}
int len = strlen(argv[1]);
int tmp[20];
int ind=0;
int pos=0;
for(int i=0;i<len;++i){
if(argv[1][i]==','){
long long val = get_val(tmp,ind);
ind=0;
i++;
arr[pos++]=val;
continue;
}
tmp[ind++]=argv[1][i]-'0';
}
arr[pos++]=get_val(tmp,ind);
int len1=pos;
ind=0,pos=0;
len=strlen(argv[2]);
for(int i=0;i<len;++i){
if(argv[2][i]==','){
long long val = get_val(tmp,ind);
ind=0;
i++;
arr1[pos++]=val;
continue;
}
tmp[ind++]=argv[2][i]-'0';
}
arr1[pos++]=get_val(tmp,ind);
memset(lc,-1,sizeof(lc));
lcs(len1-1,pos-1);
find(len1-1,pos-1);
for(int i=indic-1;i>-1;--i){
printf("%lld",ans[i]);
if(i!=0)printf(", ");
}
}
Longest Common Subsequence in C was written by:
If you see anything you'd like to change or update, please consider contributing.
No 'How to Implement the Solution' section available. Please consider contributing.
No 'How to Run the Solution' section available. Please consider contributing.