Linear Search in Ruby

Published on 29 October 2025 (Updated: 07 May 2026)

Welcome to the Linear Search in Ruby page! Here, you'll find the source code for this program as well as a description of how the program works.

Current Solution

def usage!
  abort('Usage: please provide a list of integers ("1, 4, 5, 11, 12") and the integer to find ("11")')
end

list_str, target_str = ARGV

usage! if [list_str, target_str].any? { it.to_s.strip.empty? }

numbers = list_str.split(",").map { Integer(it.strip) }
target = Integer(target_str)

puts numbers.include?(target)

Linear Search in Ruby was written by:

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How to Implement the Solution

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How to Run the Solution

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