Linear Search in Java

Welcome to the Linear Search in Java page! Here, you'll find the source code for this program as well as a description of how the program works.

Current Solution

import java.util.*;

public class LinearSearch {

    public static void main(String[] args) {
        try {
            ArrayList<Integer> listOfNumbers = new ArrayList<>();
            Integer keyToSearch = Integer.parseInt(args[1]);
            String[] NumberArray = args[0].split(",");
            for (String Number : NumberArray) {
                listOfNumbers.add(Integer.parseInt(Number.trim()));
            }
            if (listOfNumbers.size() >= 1) {
                StringBuilder output = new StringBuilder();
                Boolean searched = linearSearch(listOfNumbers, keyToSearch);
                System.out.println(searched);
            } else {
                System.out.println(
                        "Usage: please provide a list of integers (\"1, 4, 5, 11, 12\") and the integer to find (\"11\")");
            }
        } catch (Exception e) {
            System.out.println(
                    "Usage: please provide a list of integers (\"1, 4, 5, 11, 12\") and the integer to find (\"11\")");
        }
    }

    private static Boolean linearSearch(ArrayList<Integer> list, Integer keyToSearch) {
        Boolean ans = false;
        for (Integer number : list) {
            if (number == keyToSearch) {
                ans = true;
                break;
            }
        }
        return ans;
    }
}

Linear Search in Java was written by:

• Ashish Aggarwal
• Jeremy Grifski
• rzuckerm

If you see anything you'd like to change or update, please consider contributing.

How to Implement the Solution

No 'How to Implement the Solution' section available. Please consider contributing.

How to Run the Solution

No 'How to Run the Solution' section available. Please consider contributing.