Linear Search in Elixir

Linear Search

in Elixir

Welcome to the Linear Search in Elixir page! Here, you'll find the source code for this program as well as a description of how the program works.

Current Solution

defmodule LinearSearch do
  @doc """
  Searches for an integer in a list of integers from the argument list.

  Expects two arguments: a comma-separated list of integers (e.g. `"1, 4, 5, 11"`)
  and the integer to find (e.g. `"11"`).

  Returns `{:ok, true}` if found, `{:ok, false}` if not, and `:error` if arg is invalid.
  """
  @spec main(argv :: list(String.t())) :: {:ok, boolean()} | :error
  def main([list, target]) do
    with {:ok, list}  <- parse_list(list),
         {target, ""} <- Integer.parse(target)
    do
      {:ok, Enum.member?(list, target)} 
    else
      _ -> :error
    end
  end 
  def main(_), do: :error

  @spec parse_list(str :: String.t()) :: {:ok, list(integer())} | :error
  defp parse_list(""), do: :error
  defp parse_list(str) do
    str
    |> String.split(",")
    |> Enum.map(&String.trim/1)
    |> Enum.reduce_while({:ok, []}, fn n, {:ok, acc} ->
      case Integer.parse(n) do
        {n, ""} -> {:cont, {:ok, [n | acc]}}
        _       -> {:halt, :error}
      end
    end)
  end
end

case LinearSearch.main(System.argv()) do
  {:ok, res} -> IO.puts(res)
  _ -> IO.puts("Usage: please provide a list of integers (\"1, 4, 5, 11, 12\") and the integer to find (\"11\")")
end

Linear Search in Elixir was written by:

• Ricardo Mapurunga Junior

If you see anything you'd like to change or update, please consider contributing.

How to Implement the Solution

No 'How to Implement the Solution' section available. Please consider contributing.

How to Run the Solution

No 'How to Run the Solution' section available. Please consider contributing.