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Welcome to the Josephus Problem in Algol68 page! Here, you'll find the source code for this program as well as a description of how the program works.
MODE PARSEINT_RESULT = STRUCT(BOOL valid, INT value, STRING leftover);
MODE PARSEINTLIST_RESULT = STRUCT(BOOL valid, REF []INT values);
PROC parse int = (REF STRING s) PARSEINT_RESULT:
(
BOOL valid := FALSE;
REAL r := 0.0;
INT n := 0;
STRING leftover;
# Associate string with a file #
FILE f;
associate(f, s);
# On end of input, exit if valid number not seen. Otherwise ignore it #
on logical file end(f, (REF FILE dummy) BOOL:
(
IF NOT valid THEN done FI;
TRUE
)
);
# Exit if value error #
on value error(f, (REF FILE dummy) BOOL: done);
# Convert string to real number #
get(f, r);
# If real number is in range of an integer, convert to integer. Indicate integer is valid if same as real #
IF ABS r <= max int
THEN
n := ENTIER(r);
valid := (n = r)
FI;
# Get leftover string #
get(f, leftover);
done:
close(f);
PARSEINT_RESULT(valid, n, leftover)
);
PROC usage = VOID: printf(($gl$, "Usage: please input the total number of people and number of people to skip."));
COMMENT
Reference: https://en.wikipedia.org/wiki/Josephus_problem#The_general_case
Use zero-based index algorithm:
g(1, k) = 0
g(m, k) = [g(m - 1, k) + k] MOD m, for m = 2, 3, ..., n
Final answer is g(n, k) + 1 to get back to one-based index
COMMENT
PROC josephus = (INT n, INT k) INT:
(
INT g := 0;
FOR m FROM 2 TO n
DO
g := (g + k) MOD m
OD;
g + 1
);
# Parse 1st and 2nd command-line arguments #
[2]INT values;
FOR m TO 2
DO
STRING s := argv(m + 3);
PARSEINT_RESULT result := parse int(s);
# If invalid, extra characters, exit #
values[m] := value OF result;
IF NOT (valid OF result) OR (leftover OF result) /= ""
THEN
usage;
stop
FI
OD;
INT n := values[1];
INT k := values[2];
INT g := josephus(n, k);
printf(($gl$, whole(g, 0)))
Josephus Problem in Algol68 was written by:
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