Fizz Buzz in Unicat

Welcome to the Fizz Buzz in Unicat page! Here, you'll find the source code for this program as well as a description of how the program works.

Current Solution

# This program implements the fizz-buzz algorithm. It tests the math
# instructions

# Set up letters
0o00 😻😹😸🙀🙀😹😸😾🙀🙀 Memory 0 = 0o106 (70 = 'F')
0o01 😻😹😹🙀🙀😹😽😹🙀🙀 Memory 1 = 0o151 (105 = 'i')
0o02 😻😹😺🙀🙀😹😿😺🙀🙀 Memory 2 = 0o172 (122 = 'z')
0o03 😻😹😻🙀🙀😹😸😺🙀🙀 Memory 3 = 0o102 (66 = 'B')
0o04 😻😹😼🙀🙀😹😾😽🙀🙀 Memory 4 = 0o165 (117 = 'u')
0o05 😻😹😽🙀🙀😹😺🙀🙀 Memory 5 = 0o12 (10 = '\n')

# Set up constants
0o06 😻😹😾🙀🙀😸🙀🙀 Memory 6 = 0 (n)
0o07 😻😹😿🙀🙀😹🙀🙀 Memory 7 = 1
0o10 😻😹😹😸🙀🙀😻🙀🙀 Memory 8 (0o10) = 3
0o11 😻😹😹😹🙀🙀😽🙀🙀 Memory 9 (0o11) = 5

# Loop start: Increment n. If n > 100, exit
0o12 😿🙀😸😾🙀🙀😿🙀🙀 Memory 6 += Memory 7 (increment n)
0o13 😻😹😹😺🙀🙀😹😼😼🙀😿 Memory 10 (0o12) = -0o144 (-100)
0o14 😿🙀😸😹😺🙀🙀😾🙀🙀 Memory 10 (0o12) += Memory 6 (n - 100)
0o15 😽😿😹😺🙀🙀😽😼🙀🙀 If Memory 10 (0o12) > 0, jump to 0o55 (0o54 + 1) (if n > 100)

# Indicate no output
0o16 😻😹😹😻🙀🙀😸🙀🙀 Memory 11 (0o13) = 0

# If n mod 3 is 0, output "Fizz" and indicate output
0o17 😻😹😹😺🙀🙀😸🙀🙀 Memory 10 (0o12) = 0
0o20 😿🙀😸😹😺🙀🙀😾🙀🙀 Memory 10 (0o12) += Memory 6 (n)
0o21 😻😹😹😼🙀🙀😸🙀🙀 Memory 12 (0o14) = 0
0o22 😿🙀😸😹😼🙀🙀😾🙀🙀 Memory 12 (0o14) += Memory 6 (n)
0o23 😿🙀😿😹😼🙀🙀😹😸🙀🙀 Memory 12 (0o14) /= Memory 8 (0o10) (3)
0o24 😿🙀🙀😹😼🙀🙀😹😸🙀🙀 Memory 12 (0o14) *= Memory 8 (0o10) (3)
0o25 😿🙀😺😹😺🙀🙀😹😼🙀🙀 Memory 10 (0o12) -= Memory 12 (0o14) (n - floor(n / 3) * 3)
0o26 😽😿😹😺🙀🙀😻😻🙀🙀 If Memory 10 (0o12) > 0, jump to 0o34 (0o33 + 1)
0o27 😽😼😸🙀🙀 Output Memory 0 ('F')
0o30 😽😼😹🙀🙀 Output Memory 1 ('i')
0o31 😽😼😺🙀🙀 Output Memory 2 ('z')
0o32 😽😼😺🙀🙀 Output Memory 2 ('z')
0o33 😻😹😹😻🙀🙀😹🙀🙀 Memory 11 (0o13) = 1

# If n mod 5 is 0, output "Buzz" and indicate output
0o34 😻😹😹😺🙀🙀😸🙀🙀 Memory 10 (0o12) = 0
0o35 😿🙀😸😹😺🙀🙀😾🙀🙀 Memory 10 (0o12) += Memory 6 (n)
0o36 😻😹😹😼🙀🙀😸🙀🙀 Memory 12 (0o14) = 0
0o37 😿🙀😸😹😼🙀🙀😾🙀🙀 Memory 12 (0o14) += Memory 6 (n)
0o40 😿🙀😿😹😼🙀🙀😹😹🙀🙀 Memory 12 (0o14) /= Memory 9 (0o11) (floor(n / 5))
0o41 😿🙀🙀😹😼🙀🙀😹😹🙀🙀Memory 12 (0o14) *= Memory 9 (0o11) (floor(n / 5) * 5)
0o42 😿🙀😺😹😺🙀🙀😹😼🙀🙀 Memory 10 (0o12) -= Memory 12 (0o14) (n - floor(n / 5) * 5)
0o43 😽😿😹😺🙀🙀😽😸🙀🙀 If Memory 10 (0o12) > 0, jump to 0o51 (0o50 + 1)
0o44 😽😼😻🙀🙀 Output Memory 3 ('B')
0o45 😽😼😼🙀🙀 Output Memory 4 ('u')
0o46 😽😼😺🙀🙀 Output Memory 2 ('z')
0o47 😽😼😺🙀🙀 Output Memory 2 ('z')
0o50 😻😹😹😻🙀🙀😹🙀🙀 Memory 11 (0o13) = 1

# If no output, output n as value
0o51 😽😿😹😻🙀🙀😽😺🙀🙀 If Memory 11 (0o13) > 0, jump to 0o53 (0o52 + 1)
0o52 😼😼😾🙀🙀 Output Memory 6 (n) as value

# Output newline
0o53 😽😼😽🙀🙀 Output Memory 5 ('\n')

# Jump to Loop start
0o54 😻😹😹🙀😿😹😹🙀🙀 Jump to 0o12 (0o11 + 1)

0o55 🙀🙀 Exit

Fizz Buzz in Unicat was written by:

• rzuckerm

If you see anything you'd like to change or update, please consider contributing.

How to Implement the Solution

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