Fizz Buzz in Racket

Welcome to the Fizz Buzz in Racket page! Here, you'll find the source code for this program as well as a description of how the program works.

Current Solution

;fizzbuzz in racket
;Author: Emblazion

#lang racket
(for ([i (in-range 1 101)])
  (cond
    [(and
      (equal? 0 (modulo i 3))
      (equal? 0 (modulo i 5)))
     (printf "FizzBuzz\n")]
    [(equal? 0 (modulo i 3)) (printf "Fizz\n")]
    [(equal? 0 (modulo i 5)) (printf "Buzz\n")]
    [else (printf "~a\n" i)]))

Fizz Buzz in Racket was written by:

• RubinMathias

If you see anything you'd like to change or update, please consider contributing.

How to Implement the Solution

No 'How to Implement the Solution' section available. Please consider contributing.

How to Run the Solution

No 'How to Run the Solution' section available. Please consider contributing.