Fizz Buzz in Octave

Published on 01 October 2020 (Updated: 09 December 2023)

Welcome to the Fizz Buzz in Octave page! Here, you'll find the source code for this program as well as a description of how the program works.

Current Solution

function fizz_buzz()

  % Loop from 1 to 100
  for i = 1:100
    fizzbuzz = '';
    
    % Check if i is divisible by 3
    if mod(i,3) == 0
      fizzbuzz = [fizzbuzz 'Fizz'];
    end
    
    % Check if i is divisible by 5
    if mod(i,5) == 0
      fizzbuzz = [fizzbuzz 'Buzz'];
    end
    
    % If fizzbuzz variable is empty,print i
    if isempty(fizzbuzz)
      disp(i);
    else
      % If fizzbuzz variable is not empty, print the variable
      disp(fizzbuzz);
    end
  end
end

Fizz Buzz in Octave was written by:

If you see anything you'd like to change or update, please consider contributing.

How to Implement the Solution

No 'How to Implement the Solution' section available. Please consider contributing.

How to Run the Solution

No 'How to Run the Solution' section available. Please consider contributing.