Fizz Buzz in Ocaml

Published on 19 January 2025 (Updated: 19 January 2025)

Welcome to the Fizz Buzz in Ocaml page! Here, you'll find the source code for this program as well as a description of how the program works.

Current Solution

let fizzbuzz i =
  if i mod 15 == 0
  then "FizzBuzz"
  else if i mod 5 == 0
  then "Buzz"
  else if i mod 3 == 0
  then "Fizz"
  else string_of_int i
;;

for i = 1 to 100 do
  print_string (fizzbuzz(i) ^ "\n")
done;;

Fizz Buzz in Ocaml was written by:

If you see anything you'd like to change or update, please consider contributing.

How to Implement the Solution

No 'How to Implement the Solution' section available. Please consider contributing.

How to Run the Solution

No 'How to Run the Solution' section available. Please consider contributing.