Fizz Buzz in Euphoria

Published on 19 February 2023 (Updated: 19 February 2023)

Welcome to the Fizz Buzz in Euphoria page! Here, you'll find the source code for this program as well as a description of how the program works.

Current Solution

include std/io.e
include std/math.e
include std/utils.e

for n = 1 to 100
do
    sequence s = ""
    s &= iif(mod(n, 3) = 0, "Fizz", "")
    s &= iif(mod(n, 5) = 0, "Buzz", "")
    s &= iif(length(s) = 0, sprintf("%d", n), "")
    printf(STDOUT, "%s\n", {s})
end for

Fizz Buzz in Euphoria was written by:

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How to Implement the Solution

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How to Run the Solution

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