Fizz Buzz in Elixir

Published on 28 April 2022 (Updated: 25 September 2022)

Fizz Buzz in Elixir

Welcome to the Fizz Buzz in Elixir page! Here, you'll find the source code for this program as well as a description of how the program works.

Current Solution

1..100
|> Enum.map(fn
  n when rem(n, 3) == 0 and rem(n, 5) == 0 -> "FizzBuzz"
  n when rem(n, 3) == 0 -> "Fizz"
  n when rem(n, 5) == 0 -> "Buzz"
  n -> Integer.to_string(n)
end)
|> Enum.each(&IO.puts/1)

Fizz Buzz in Elixir was written by:

If you see anything you'd like to change or update, please consider contributing.

How to Implement the Solution

No 'How to Implement the Solution' section available. Please consider contributing.

How to Run the Solution

No 'How to Run the Solution' section available. Please consider contributing.