Even Odd in Php

Welcome to the Even Odd in Php page! Here, you'll find the source code for this program as well as a description of how the program works.

Current Solution

<?php

if ($argc < 2 || !is_numeric($argv[1])) {
    die("Usage: please input a number\n");
}

$input = abs($argv[1]);

if ($input % 2 == 0) {
    echo "Even\n";
} elseif ($input % 2 == 1) {
    echo "Odd\n";
}

Even Odd in Php was written by:

• Berry Semexan
• Jeremy Grifski

If you see anything you'd like to change or update, please consider contributing.

How to Implement the Solution

No 'How to Implement the Solution' section available. Please consider contributing.

How to Run the Solution

No 'How to Run the Solution' section available. Please consider contributing.