Binary Search in Typescript

Published on 07 October 2023 (Updated: 07 October 2023)

Welcome to the Binary Search in Typescript page! Here, you'll find the source code for this program as well as a description of how the program works.

Current Solution

const error_msg: string = "Usage: please provide a list of sorted integers (\"1, 4, 5, 11, 12\") and the integer to find (\"11\")";
if (process.argv.length != 4) {
    console.log(error_msg);
    process.exit(1);
}

let list_str: string = process.argv[2]
let target: number = parseInt(process.argv[3]);

if (isNaN(target) || list_str.length == 0) {
    console.log(error_msg);
    process.exit(1);
}
let list: number[] = list_str.split(",").map((x: string) => parseInt(x));
// check if list is sorted
for (let i: number = 1; i < list.length; i++) {
    if (list[i] < list[i - 1]) {
        console.log(error_msg);
        process.exit(1);
    }
}
let found: boolean = false;
let low: number = 0;
let high: number = list.length - 1;
while (low <= high) {
    let mid: number = Math.floor((low + high) / 2);
    if (list[mid] == target) {
        found = true;
        break;
    }
    if (list[mid] < target) {
        low = mid + 1;
    } else {
        high = mid - 1;
    }
}
console.log(found ? "true" : "false");

Binary Search in Typescript was written by:

If you see anything you'd like to change or update, please consider contributing.

How to Implement the Solution

No 'How to Implement the Solution' section available. Please consider contributing.

How to Run the Solution

No 'How to Run the Solution' section available. Please consider contributing.