Baklava in Red

Published on 17 October 2024 (Updated: 17 October 2024)

Welcome to the Baklava in Red page! Here, you'll find the source code for this program as well as a description of how the program works.

Current Solution

Red [Title: "Bakalava"]

s: ""
repeat i 21 [
    numSpaces: i - 11
    if numSpaces < 0 [numSpaces: 0 - numSpaces]
    clear s
    insert/dup tail s " " numSpaces
    insert/dup tail s "*" (21 - (2 * numSpaces))
    print s
]

Baklava in Red was written by:

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How to Implement the Solution

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How to Run the Solution

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