Baklava in Euphoria

Published on 28 April 2022 (Updated: 26 March 2023)

Baklava in Euphoria

Welcome to the Baklava in Euphoria page! Here, you’ll find the source code for this program as well as a description of how the program works.

Current Solution

include std/io.e
include std/math.e

for n = -10 to 10
do
    integer num_spaces = abs(n)
    integer num_stars = 21 - 2 * num_spaces
    printf(STDOUT, "%s%s\n", {repeat(' ', num_spaces), repeat('*', num_stars)})
end for

Baklava in Euphoria was written by:

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How to Implement the Solution

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How to Run the Solution

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